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The best introductory book is _Photoshop For Dummies,_ by Brian J. Ward. The introduction is up-to-the-minute and informs readers about the most current software versions.

Comparing Photoshop to Other Desktop Publishing Software

Although Photoshop is the industry standard, it isn’t the only tool available to the desktop publisher. In fact, these other programs work like Photoshop in many ways, but they’re rarely used for desktop publishing.

Photoshop competes with the following programs as the industry standard:

Adobe Illustrator: This program supports raster and vector image editing and combines text and images into a single document, or layout. This program enables you to create an integrated page, that is, a single image that includes text, line art, and any other type of image.

Illustrator lacks the practical and productive tools for desktop publishing, though it can be used for specific print and online projects.

Photoshop: The industry standard image editing program. You can make raster or vector images, which means any type of image — a photo, a line drawing, a chart, or a line graph. Vector art looks sharp and is ideal for printing and publishing.

Illustrator and Photoshop complement each other; the pros who spend their time doing print and online projects choose Photoshop while the pros who work in the print industry choose Illustrator.

Although these two programs are used for many of the same types of projects, the differences between them are often significant. For example:

Photoshop is designed to work efficiently for large projects. It uses a nonlinear editing system that enables you to work more easily and quickly, which is a huge advantage for large projects. If you’ve ever used a computer graphics program, you’ll appreciate the nonlinear editor.

Illustrator is suited for creating small or moderately sized projects. If you’re just drawing line art or adding color to a photo, Illustrator may be easier to use.

Photoshop has numerous tools and features that can assist in creating the best possible project. Illustrator has a much more basic set of editing tools, though you can access many of the tools in Photoshop.

Photoshop is a full-featured application, which means that it covers every aspect of image creation and editing. Illustrator is a more basic tool, and it doesn’t offer the same editing options, among other things. But a good illustration program should have a few editing tools.

If you’re very familiar

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The latest version of Photoshop Elements is 11.0, available for Windows and Mac OS as a free download.

The latest version of Photoshop Elements is 11.0, available for Windows and Mac OS as a free download. Read on to see how to use and set up Photoshop Elements 11.

Adobe Photoshop Elements 11.0 for Windows

Adobe Photoshop Elements 11.0 for Mac

The main screen of the Adobe Photoshop Elements 11.0 application for Windows and Mac

The application’s main window

1. Creating a New Work File

Open the image you want to work on.

After creating a new work file, Photoshop Elements offers the following two options:

Image > Adjustments > Enhance > [create a new adjustment layer] > Apply: Photoshop Elements will open the image with the new adjustment layer;

Image > Adjustments > [create a new adjustment layer] > [select contents] > Apply: Photoshop Elements will open the image with the new adjustment layer.

You have two options to create a new layer in the adjustments panel:

Fill with foreground color

Create new layer

Select Fill with foreground color to add a new layer filled with the color of the existing foreground layer.

Select Create new layer to add a new layer with the current color as the new layer’s color. To create a new layer, you need a fully opened image (one layer below the current layer).

In the current illustration, the image has 3 layers: the background (white), the main image (green), and the adjustment layer, which is gray (below in the illustration). I am creating a new layer above the adjustment layer. The new layer is pink. To create the new layer, I select “Create new layer” in the adjustments panel. I also deselect the entire “Adjustments” layer so the “Main Image” layer below remains. I click the cross button in the bottom of the “Create new layer” window to create the new layer. The image is now black with the pink layer above it.

Select image > Adjustments > Enhance > [create a new adjustment layer] > Apply: to add a new adjustment layer above the image and a pink layer to it, and move the current layer to the top of the layers panel.

A pink adjustment layer appears. Because the other layer is black, I deselect it. I
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Effects of ultrasonic emulsification and different stabilizers on the physical properties of soy protein isolate emulsions.
Ultrasonic treatment was used to generate aqueous emulsions of soy protein isolate (SPI) by controlling the ratios of its three components, soy protein isolate (SPI, 81.2%), soy oil (13.4%) and glycerol (5.4%). The effects of four factors, surfactant type (Tween 20, Span 20 or Tween 20/Span 20 mixture), SPI concentration (0.3-2%), ultrasonic power (0-50%), and emulsification time (5-45 min) on the emulsion characteristics were studied. The emulsion creaming stability was determined as a function of surface tension. The emulsion drop size was measured with a dynamic light scattering (DLS) system. The zeta potential was determined with a Zetasizer. All the physical properties followed nonlinear trends with increasing ultrasonic power and time, and decreasing SPI concentration or oil content. High correlation was seen between ultrasonic power and the physical properties of the emulsion. The Span 20/SPI ratio of the emulsion was also shown to affect the physical properties in comparison to those of the Tween 20/SPI ratio. The physical stability of the emulsion was increased by changing the ratio of the three components. These properties could be controlled by ultrasonic treatment. interest. Professor Sang-Hoon Cho has been a member of the Korean Health Technology Assessment (HTA) board for the past 5 years, and the board is expected to be the HTA body for the Korean National Health Insurance Program by 2018. The other authors have no conflicts of interest to disclose. This study was supported by a grant from the Korean Health Technology R&D project, Ministry of Health & Welfare, Republic of Korea (HI14C2328). The funding body had no involvement in the study design, data collection, data analysis, data interpretation, or writing of the report. The corresponding author had full access to all of the data in the study and had final responsibility for the decision to submit for publication.

![The workflow of the overall study. Abbreviations: CPT, Clinical Practice Guidelines; DART, development of evidence-based recommendations and tools. CPG, Clinical Practice Guidelines; DBR, Decision-Making Bundle Recommendations; NICE, UK, The National Institute for Health and Clinical Excellence; AD, adequate dissemination.]

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Q:

Identity of Galois groups of different polynomial extensions of a field

Suppose that $p$ and $q$ are two irreducible polynomials of degrees $\alpha$ and $\beta$ in a field $K$, respectively, and that $f(y)=y^{\alpha}-p(x)$, $g(y)=y^{\beta}-q(x)$ are their corresponding splitting fields.

Why is it true that the Galois group of $f$ over $K$ is $S_{\alpha}$ if and only if the Galois group of $g$ over $K$ is $S_{\beta}$?

I thought of trying to prove this using the polynomial $F(x,y)=x^{\alpha}-y^{\alpha}-p(x)-q(x)$, but the situation does not seem to change.
Thanks.

A:

In your case, the answer is actually easy, because you have defined $f$ and $g$ in such a nice way. You’ve probably already noticed this, but for the sake of completeness, let me give the proof.
Suppose that the Galois group of $f$ over $K$ is $S_{\alpha}$, and let $E$ be a splitting field for $f$ over $K$. Then $[E:K]=\alpha$, so the minimal polynomial for $y$ over $K$ is $y^{\alpha}-p(x)$, by definition of $f$. This follows because the minimal polynomial for $y$ over $K$ divides $f$ by definition, and $f$ has a root in $E$ by the ring theorem.
By the same argument, the Galois group of $g$ over $K$ is $S_{\beta}$.
Now, if the Galois group of $f$ is $S_{\alpha}$, then it’s also the Galois group of $f$ over $E$. If the Galois group of $g$ is $S_{\beta}$, then it’s also the Galois group of $g$ over $E$. Thus, we have shown that $S_{\alpha}\cong S_{\beta}$ by transitivity.

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